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Thread Statistics | Show CCP posts - 3 post(s) |
postapo wastelander
Corrosive Synergy RISE of LEGION
1038
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Posted - 2015.03.08 16:28:00 -
[1] - Quote
Big Burns wrote:CCP Rattati wrote:These are all answered in my previous blogs/threads.
Step 1) All squads and individuals are converted to units. Each unit is the sum of Mu of all the individuals in the squad.
Step 2) Multiplier is applied to all units
Step 3) The highest value unit is placed randomly on Team A or Team B, let's say Team A for simplicity.
Step 4) Units are placed on the opposite Team, Team B, until the sum on Team B exceeds Team A.
Step 5) Units are placed on Team A until the sum of Mu exceeds Team B or either team has 16 player. Then the rest go on the other team.
Step 6) Repeat until all units have been placed.
This method guarantees that the two best squads are always on opposite sides.
It also guarantees that the second best and third best squads are on the opposite side of the best squad.
If there is a single 6 man squad and no other squads, it gets placed on one Team and ALL the best individuals on the opposite side, due to the multiplier, usually 8-10 of the best solo players fight the 6 man squad.
Finally, this method has never been shown to have not worked as intended. Players concern is usually because the second best squad isn't all in the same corporation so it looks like randoms. My only response to this is....#BringBackCubs!
My only responce to this is..#BanAllSpammers!
"Sebiestor Hetzer"
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postapo wastelander
Corrosive Synergy RISE of LEGION
1062
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Posted - 2015.03.08 23:00:00 -
[2] - Quote
CCP Rattati wrote:These are all answered in my previous blogs/threads.
Step 1) All squads and individuals are converted to units. Each unit is the sum of Mu of all the individuals in the squad.
Step 2) Multiplier is applied to all units
Step 3) The highest value unit is placed randomly on Team A or Team B, let's say Team A for simplicity.
Step 4) Units are placed on the opposite Team, Team B, until the sum on Team B exceeds Team A.
Step 5) Units are placed on Team A until the sum of Mu exceeds Team B or either team has 16 player. Then the rest go on the other team.
Step 6) Repeat until all units have been placed.
This method guarantees that the two best squads are always on opposite sides.
It also guarantees that the second best and third best squads are on the opposite side of the best squad.
If there is a single 6 man squad and no other squads, it gets placed on one Team and ALL the best individuals on the opposite side, due to the multiplier, usually 8-10 of the best solo players fight the 6 man squad.
Finally, this method has never been shown to have not worked as intended. Players concern is usually because the second best squad isn't all in the same corporation so it looks like randoms.
BUT
Rattati the major issue is if you have two squad synced for battle on one side the MU do not see "there is need to put another two squads on other one".
If you will have one group and some loners on both side the MU system will works, but with two groups syncs you need to implement more than just MU system.
"Sebiestor Hetzer"
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postapo wastelander
Corrosive Synergy RISE of LEGION
1066
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Posted - 2015.03.09 09:03:00 -
[3] - Quote
Maken Tosch wrote:postapo wastelander wrote:CCP Rattati wrote:These are all answered in my previous blogs/threads.
Step 1) All squads and individuals are converted to units. Each unit is the sum of Mu of all the individuals in the squad.
Step 2) Multiplier is applied to all units
Step 3) The highest value unit is placed randomly on Team A or Team B, let's say Team A for simplicity.
Step 4) Units are placed on the opposite Team, Team B, until the sum on Team B exceeds Team A.
Step 5) Units are placed on Team A until the sum of Mu exceeds Team B or either team has 16 player. Then the rest go on the other team.
Step 6) Repeat until all units have been placed.
This method guarantees that the two best squads are always on opposite sides.
It also guarantees that the second best and third best squads are on the opposite side of the best squad.
If there is a single 6 man squad and no other squads, it gets placed on one Team and ALL the best individuals on the opposite side, due to the multiplier, usually 8-10 of the best solo players fight the 6 man squad.
Finally, this method has never been shown to have not worked as intended. Players concern is usually because the second best squad isn't all in the same corporation so it looks like randoms. BUT Rattati the major issue is if you have two squad synced for battle on one side the MU do not see "there is need to put another two squads on other one". If you will have one group and some loners on both side the MU system will works, but with two groups syncs you need to implement more than just MU system. If the steps listed by CCP Rattati are correct, then it shouldn't be possible for two squads of the same group to q-sync into the same team. One squad would be in Team A while the other squad that q-synced would be put on Team B. At least that's how it's suppose to work right now.
I think there is language barier (from my side ofcourse).
What i meant was give a MU implement what push wih to put qsynced people against themselves. If there will be two groups, there should be two groups on both sides. That will works better than only qsynced squad on one side against lonely mercs on other.
"Sebiestor Hetzer"
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