DUST Search - Questions CCP Rattati did not answer about teambuilder

CCP Rattati wrote:

These are all answered in my previous blogs/threads.

Step 1)
All squads and individuals are converted to units. Each unit is the sum of Mu of all the individuals in the squad.

Step 2)
Multiplier is applied to all units

Step 3)
The highest value unit is placed randomly on Team A or Team B, let's say Team A for simplicity.

Step 4)
Units are placed on the opposite Team, Team B, until the sum on Team B exceeds Team A.

Step 5)
Units are placed on Team A until the sum of Mu exceeds Team B or either team has 16 player. Then the rest go on the other team.

Step 6)
Repeat until all units have been placed.

This method guarantees that the two best squads are always on opposite sides.

It also guarantees that the second best and third best squads are on the opposite side of the best squad.

If there is a single 6 man squad and no other squads, it gets placed on one Team and ALL the best individuals on the opposite side, due to the multiplier, usually 8-10 of the best solo players fight the 6 man squad.

Finally, this method has never been shown to have not worked as intended. Players concern is usually because the second best squad isn't all in the same corporation so it looks like randoms.


Author	Thread Statistics \| Show CCP posts - 3 post(s)
Vesta Opalus T.H.I.R.D R.O.C.K RISE of LEGION 484	Posted - 2015.03.09 19:22:00 - [1] - Quote CCP Rattati wrote: These are all answered in my previous blogs/threads. Step 1) All squads and individuals are converted to units. Each unit is the sum of Mu of all the individuals in the squad. Step 2) Multiplier is applied to all units Step 3) The highest value unit is placed randomly on Team A or Team B, let's say Team A for simplicity. Step 4) Units are placed on the opposite Team, Team B, until the sum on Team B exceeds Team A. Step 5) Units are placed on Team A until the sum of Mu exceeds Team B or either team has 16 player. Then the rest go on the other team. Step 6) Repeat until all units have been placed. This method guarantees that the two best squads are always on opposite sides. It also guarantees that the second best and third best squads are on the opposite side of the best squad. If there is a single 6 man squad and no other squads, it gets placed on one Team and ALL the best individuals on the opposite side, due to the multiplier, usually 8-10 of the best solo players fight the 6 man squad. Finally, this method has never been shown to have not worked as intended. Players concern is usually because the second best squad isn't all in the same corporation so it looks like randoms. I had a few matches in a row last night where I was the only person on my team who went positive in KDR, I went like 11-1, 8-2, etc, everyone else on the team was completely stomped. Could the current matchmaking system result in a circumstance where SQUAD 1 (the stompers on the other team) is #1 in MU, then one person on the other team is #2 in MU (in this example, that would be me), then a bunch of low MU players would fill out the rest of the slots? I think the biggest remaining problem in matchmaking is that the matchmaking thinks its ok to put players with 1 MU up against people with 1000 MU (values are examples based on what I just pulled out of my butt). All those low MU players just need to be removed from the equation and put into their own game. They shouldnt even be matched up in games where people like me or that opposing squad exist. They just cant compete. Even if they are matched with a high MU squad on the same team, they are still just food for the opposing high MU players.